2013年9月20日星期五

1Z0-047 dernières questions d'examen certification Oracle et réponses publiés

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Code d'Examen: 1Z0-047
Nom d'Examen: Oracle (Oracle Database SQL Expert)
Questions et réponses: 260 Q&As

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NO.1 View the Exhibit and examine the descriptions of ORDER_ITEMS and ORDERS tables. You want to
display the CUSTOMER_ID, PRODUCT_ID, and total (UNIT_PRICE multiplied by QUANTITY) for the
order placed. You also want to display the subtotals for a CUSTOMER_ID as well as for a PRODUCT_ID
for the last six months. Which SQL statement would you execute to get the desired output?
A.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
B.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id,oi.product_id) HAVING
MONTHS_BETWEEN(order_date, SYSDATE) <= 6;
C.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id GROUP BY ROLLUP (o.customer_id, oi.product_id) WHERE
MONTHS_BETWEEN(order_date, SYSDATE) >= 6;
D.SELECT o.customer_id, oi.product_id, SUM(oi.unit_price*oi.quantity) "Total" FROM order_items oi
JOIN orders o ON oi.order_id=o.order_id WHERE MONTHS_BETWEEN(order_date, SYSDATE) <= 6
GROUP BY ROLLUP (o.customer_id, oi.product_id) ;
Answer:D

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NO.2 View the Exhibit and examine the structure of the EMP table which is not partitioned and not an
index-organized table. Evaluate the following SQL statement: ALTER TABLE emp DROP COLUMN
first_name; Which two statements are true regarding the above command? (Choose two.)
A.The FIRST_NAME column would be dropped provided it does not contain any data.
B.The FIRST_NAME column would be dropped provided at least one or more columns remain in the table.
C.The FIRST_NAME column can be rolled back provided the SET UNUSED option is added to the above
SQL statement.
D.The FIRST_NAME column can be dropped even if it is part of a composite PRIMARY KEY provided the
CASCADE option is used.
Answer:B D

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NO.3 View the Exhibit and examine the description of the ORDERS table. Which two WHERE clause
conditions demonstrate the correct usage of conversion functions? (Choose two.)
A.WHERE order_date > TO_DATE('JUL 10 2006','MON DD YYYY')
B.WHERE TO_CHAR(order_date,'MON DD YYYY') = 'JAN 20 2003'
C.WHERE order_date > TO_CHAR(ADD_MONTHS(SYSDATE,6),'MON DD YYYY')
D.WHERE order_date IN ( TO_DATE('Oct 21 2003','Mon DD YYYY'), TO_CHAR('NOV 21 2003','Mon DD
YYYY') )
Answer:A B

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NO.4 View the Exhibit and examine PRODUCTS and ORDER_ITEMS tables. You executed the following
query to display PRODUCT_NAME and the number of times the product has been ordered: SELECT
p.product_name, i.item_cnt FROM (SELECT product_id, COUNT (*) item_cnt FROM order_items
GROUP BY product_id) i RIGHT OUTER JOIN products p ON i.product_id = p.product_id; What would
happen when the above statement is executed?
A.The statement would execute successfully to produce the required output.
B.The statement would not execute because inline views and outer joins cannot be used together.
C.The statement would not execute because the ITEM_CNT alias cannot be displayed in the outer query.
D.The statement would not execute because the GROUP BY clause cannot be used in the inline view.
Answer:A

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NO.5 View the Exhibit and examine the description of the EMPLOYEES table. You want to display the
EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT_ID for all the employees who work in the same
department and have the same manager as that of the employee having EMPLOYEE_ID 104. To
accomplish the task, you execute the following SQL statement: SELECT employee_id, first_name,
department_id FROM employees WHERE (manager_id, department_id) =(SELECT department_id,
manager_id FROM employees WHERE employee_id = 104) AND employee_id <> 104; When you
execute the statement it does not produce the desired output. What is the reason for this?
A.The WHERE clause condition in the main query is using the = comparison operator, instead of EXISTS.
B.The WHERE clause condition in the main query is using the = comparison operator, instead of the IN
operator.
C.The WHERE clause condition in the main query is using the = comparison operator, instead of the =
ANY operator.
D.The columns in the WHERE clause condition of the main query and the columns selected in the
subquery should be in the same order.
Answer:D

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NO.6 OE and SCOTT are the users in the database. The ORDERS table is owned by OE. Evaluate the
statements issued by the DBA in the following sequence: CREATE ROLE r1; GRANT SELECT, INSERT
ON oe.orders TO r1; GRANT r1 TO scott; GRANT SELECT ON oe.orders TO scott; REVOKE SELECT
ON oe.orders FROM scott; What would be the outcome after executing the statements?
A.SCOTT would be able to query the OE.ORDERS table.
B.SCOTT would not be able to query the OE.ORDERS table.
C.The REVOKE statement would remove the SELECT privilege from SCOTT as well as from the role R1.
D.The REVOKE statement would give an error because the SELECT privilege has been granted to the
role R1.
Answer:A

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NO.7 View the Exhibit and examine the description of the CUSTOMERS table. You want to add a constraint
on the CUST_FIRST_NAME column of the CUSTOMERS table so that the value inserted in the column
does not have numbers. Which SQL statement would you use to accomplish the task?
A.ALTER TABLE CUSTOMERS ADD CONSTRAINT cust_f_name
CHECK(REGEXP_LIKE(cust_first_name,'

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